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Tengsizliklar va ularning sistemasi — test savollari javoblari bilan (4-sahifa)

Matematika · 40 ta ochiq savol (bankda jami 390 ta) · har birida to'g'ri javob va izoh
Shu mavzudan test ishlash Matematika — barcha mavzular
31. $|x + 3| + |x - 1| \leq 6$ tengsizlikni yeching.
  1. A) $-4 \leq x \leq 2$
  2. B) $-3 \leq x \leq 2$
  3. C) $-4 < x < 2$
  4. D) $-2 \leq x \leq 4$
Javobni ko'rish

To'g'ri javob: A) $-4 \leq x \leq 2$

32. $\begin{cases} x > 2p - 1 \\ x < 3 - p \end{cases}$ sistemasining yechimga ega bo'lishi uchun $p$ ning qiymatlari diapazonini toping.
  1. A) $p < \dfrac{4}{3}$
  2. B) $p > \dfrac{4}{3}$
  3. C) $p < \dfrac{3}{4}$
  4. D) $p > \dfrac{3}{4}$
Javobni ko'rish

To'g'ri javob: A) $p < \dfrac{4}{3}$

33. $|ax - 2| < 4$ tengsizligining yechim kesmasining uzunligi $4$ ga teng bo'lishi uchun $a$ ni toping.
  1. A) $a = 2$ faqat
  2. B) $a = -2$ faqat
  3. C) $a = \pm 2$
  4. D) $a = \pm 4$
Javobni ko'rish

To'g'ri javob: C) $a = \pm 2$

34. $\dfrac{2}{x-1} > 3$ tengsizlikni yeching ($x \neq 1$).
  1. A) $1 < x < \dfrac{5}{3}$
  2. B) $x < 1$ yoki $x > \dfrac{5}{3}$
  3. C) $x > \dfrac{5}{3}$
  4. D) $1 < x < \dfrac{3}{5}$
Javobni ko'rish

To'g'ri javob: A) $1 < x < \dfrac{5}{3}$

35. $\begin{cases} 2x - y > 3 \\ x + y < 6 \end{cases}$ sistemasida $x = 2$ bo'lsa, $y$ qanday shartni qanoatlantiradi?
  1. A) $y < 1$
  2. B) $y < 4$
  3. C) $1 < y < 4$
  4. D) $y > 1$
Javobni ko'rish

To'g'ri javob: B) $y < 4$

36. $a \cdot |x| > x - 1$ tengsizligi barcha haqiqiy $x$ uchun o'rinli bo'lishi uchun $a$ qanday bo'lishi kerak?
  1. A) $a \geq 1$
  2. B) $a > 1$
  3. C) $a \geq -1$
  4. D) $a > 0$
Javobni ko'rish

To'g'ri javob: C) $a \geq -1$

37. $|x - 2| \leq 2x - 1$ tengsizlikni yeching.
  1. A) $x \geq 1$
  2. B) $x \geq \dfrac{1}{2}$
  3. C) $x \geq 2$
  4. D) $1 \leq x \leq 3$
Javobni ko'rish

To'g'ri javob: A) $x \geq 1$

38. $\dfrac{x^2-1}{x-1} > x + 2$ tengsizligini yeching ($x \neq 1$).
  1. A) $x > 1$
  2. B) $x < 1$
  3. C) Barcha $x \neq 1$
  4. D) Yechim yo'q
Javobni ko'rish

To'g'ri javob: D) Yechim yo'q

39. $\begin{cases} |x - a| < 2 \\ |x + 1| > 3 \end{cases}$ sistemasi yechimga ega bo'lishi uchun $a$ ning qiymatlari diapazonini toping.
  1. A) $a < -2$ yoki $a > 0$
  2. B) $-2 < a < 0$
  3. C) $a < -2$ yoki $a > 2$
  4. D) $a > 0$
Javobni ko'rish

To'g'ri javob: A) $a < -2$ yoki $a > 0$

40. $\begin{cases} x > a \\ x < 2a - 3 \end{cases}$ sistemasining yechimi bo'lmasligi uchun $a$ ning qiymatlari diapazonini toping.
  1. A) $a \leq 3$
  2. B) $a < 3$
  3. C) $a \geq 3$
  4. D) $a > 3$
Javobni ko'rish

To'g'ri javob: A) $a \leq 3$

Bu — mavzuning ochiq namuna qismi. To'liq bank, vaqt rejimi, tahlil va xatolar ustida ishlash — test rejimida.